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0.4x^2+30=400/x+2
We move all terms to the left:
0.4x^2+30-(400/x+2)=0
Domain of the equation: x+2)!=0We get rid of parentheses
x∈R
0.4x^2-400/x-2+30=0
We multiply all the terms by the denominator
(0.4x^2)*x-2*x+30*x-400=0
We add all the numbers together, and all the variables
28x+(0.4x^2)*x-400=0
We multiply parentheses
0x^2+28x-400=0
We add all the numbers together, and all the variables
x^2+28x-400=0
a = 1; b = 28; c = -400;
Δ = b2-4ac
Δ = 282-4·1·(-400)
Δ = 2384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2384}=\sqrt{16*149}=\sqrt{16}*\sqrt{149}=4\sqrt{149}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-4\sqrt{149}}{2*1}=\frac{-28-4\sqrt{149}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+4\sqrt{149}}{2*1}=\frac{-28+4\sqrt{149}}{2} $
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